2(1[3y-7]1)=16

Solution for 2(1[3y-7]1)=16 equation:

Simplifying
2(1[3y + -7] * 1) = 16

Reorder the terms:
2(1[-7 + 3y] * 1) = 16

Reorder the terms for easier multiplication:
2(1 * 1[-7 + 3y]) = 16

Multiply 1 * 1
2(1[-7 + 3y]) = 16
2([-7 * 1 + 3y * 1]) = 16
2([-7 + 3y]) = 16
(-7 * 2 + 3y * 2) = 16
(-14 + 6y) = 16

Solving
-14 + 6y = 16

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '14' to each side of the equation.
-14 + 14 + 6y = 16 + 14

Combine like terms: -14 + 14 = 0
0 + 6y = 16 + 14
6y = 16 + 14

Combine like terms: 16 + 14 = 30
6y = 30

Divide each side by '6'.
y = 5

Simplifying
y = 5